Search a number
-
+
5347435 = 517531187
BaseRepresentation
bin10100011001100001101011
3101001200022011
4110121201223
52332104220
6310340351
763311122
oct24314153
911050264
105347435
113022675
12195a6b7
131152c82
149d2ab9
1570965a
hex51986b

5347435 has 16 divisors (see below), whose sum is σ = 6928416. Its totient is φ = 3947008.

The previous prime is 5347423. The next prime is 5347483.

5347435 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 5347435 - 25 = 5347403 is a prime.

It is a super-2 number, since 2×53474352 = 57190122158450, which contains 22 as substring.

It is a d-powerful number, because it can be written as 53 + 312 + 47 + 7 + 47 + 314 + 53 .

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5347397 and 5347406.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3912 + ... + 5098.

It is an arithmetic number, because the mean of its divisors is an integer number (433026).

Almost surely, 25347435 is an apocalyptic number.

5347435 is a deficient number, since it is larger than the sum of its proper divisors (1580981).

5347435 is a wasteful number, since it uses less digits than its factorization.

5347435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1262.

The product of its digits is 25200, while the sum is 31.

The square root of 5347435 is about 2312.4521616674. The cubic root of 5347435 is about 174.8699441859.

Subtracting from 5347435 its product of digits (25200), we obtain a palindrome (5322235).

The spelling of 5347435 in words is "five million, three hundred forty-seven thousand, four hundred thirty-five".

Divisors: 1 5 17 53 85 265 901 1187 4505 5935 20179 62911 100895 314555 1069487 5347435