Base | Representation |
---|---|
bin | 11000010101001011100001… |
… | …10100001101010100110111 |
3 | 21000102221221200111012001011 |
4 | 30022211300310031110313 |
5 | 24003103301341344120 |
6 | 305443311455213051 |
7 | 14161362304016542 |
oct | 1412456064152467 |
9 | 230387850435034 |
10 | 53504300340535 |
11 | 16059056762800 |
12 | 60015a9b17187 |
13 | 23b15842ac135 |
14 | d2d89c8d9859 |
15 | 62bb827d6c5a |
hex | 30a970d0d537 |
53504300340535 has 96 divisors (see below), whose sum is σ = 72698312558592. Its totient is φ = 37751313600000.
The previous prime is 53504300340523. The next prime is 53504300340607.
53504300340535 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53504300340535 - 241 = 51305277084983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3677011510 + ... + 3677026060.
It is an arithmetic number, because the mean of its divisors is an integer number (757274089152).
Almost surely, 253504300340535 is an apocalyptic number.
53504300340535 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53504300340535 is a deficient number, since it is larger than the sum of its proper divisors (19194012218057).
53504300340535 is a wasteful number, since it uses less digits than its factorization.
53504300340535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15437 (or 15426 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 40.
It can be divided in two parts, 53504300 and 340535, that added together give a palindrome (53844835).
The spelling of 53504300340535 in words is "fifty-three trillion, five hundred four billion, three hundred million, three hundred forty thousand, five hundred thirty-five".
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