Base | Representation |
---|---|
bin | 110001110110110001… |
… | …101010111100100000 |
3 | 12010011202112122011021 |
4 | 301312301222330200 |
5 | 1334113234340000 |
6 | 40331543455224 |
7 | 3603403245046 |
oct | 616661527440 |
9 | 163152478137 |
10 | 53532340000 |
11 | 20780679407 |
12 | a45ba57514 |
13 | 5081820439 |
14 | 283b90a396 |
15 | 15d4a3e11a |
hex | c76c6af20 |
53532340000 has 120 divisors (see below), whose sum is σ = 135258850188. Its totient is φ = 20833920000.
The previous prime is 53532339967. The next prime is 53532340007. The reversal of 53532340000 is 4323535.
It is a happy number.
53532340000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 10 ways, for example, as 1437016464 + 52095323536 = 37908^2 + 228244^2 .
It is a super-2 number, since 2×535323400002 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (53532340007) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 703830 + ... + 776170.
Almost surely, 253532340000 is an apocalyptic number.
53532340000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53532340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (67629425094).
53532340000 is an abundant number, since it is smaller than the sum of its proper divisors (81726510188).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53532340000 is an equidigital number, since it uses as much as digits as its factorization.
53532340000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72408 (or 72385 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 25.
Adding to 53532340000 its reverse (4323535), we get a palindrome (53536663535).
The spelling of 53532340000 in words is "fifty-three billion, five hundred thirty-two million, three hundred forty thousand".
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