Base | Representation |
---|---|
bin | 100110111101010011110… |
… | …1010100011100000000001 |
3 | 200221212111022111000020012 |
4 | 1031322213222203200001 |
5 | 1200211143100420340 |
6 | 15215430103354305 |
7 | 1061560406530424 |
oct | 115724752434001 |
9 | 20855438430205 |
10 | 5354342201345 |
11 | 1784844648a65 |
12 | 72585a452995 |
13 | 2cabb24398a7 |
14 | 147219ba99bb |
15 | 9442aa93565 |
hex | 4dea7aa3801 |
5354342201345 has 8 divisors (see below), whose sum is σ = 6704567626176. Its totient is φ = 4097235771376.
The previous prime is 5354342201287. The next prime is 5354342201401. The reversal of 5354342201345 is 5431022434535.
5354342201345 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5354342201345 - 218 = 5354341939201 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23279748587 + ... + 23279748816.
It is an arithmetic number, because the mean of its divisors is an integer number (838070953272).
Almost surely, 25354342201345 is an apocalyptic number.
It is an amenable number.
5354342201345 is a deficient number, since it is larger than the sum of its proper divisors (1350225424831).
5354342201345 is a wasteful number, since it uses less digits than its factorization.
5354342201345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46559497431.
The product of its (nonzero) digits is 864000, while the sum is 41.
The spelling of 5354342201345 in words is "five trillion, three hundred fifty-four billion, three hundred forty-two million, two hundred one thousand, three hundred forty-five".
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