Base | Representation |
---|---|
bin | 11000011000010100111010… |
… | …11001001101110010000011 |
3 | 21000211022000220020222222101 |
4 | 30030022131121031302003 |
5 | 24011341220114443020 |
6 | 310005112402451231 |
7 | 14202240543365020 |
oct | 1414123531156203 |
9 | 230738026228871 |
10 | 53612422421635 |
11 | 1609a99a869620 |
12 | 601a543963b17 |
13 | 23bb825706c0c |
14 | d34bd8522547 |
15 | 62e8aead400a |
hex | 30c29d64dc83 |
53612422421635 has 128 divisors (see below), whose sum is σ = 85300176439296. Its totient is φ = 31317074903040.
The previous prime is 53612422421581. The next prime is 53612422421647.
It is a happy number.
53612422421635 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53612422421635 - 217 = 53612422290563 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 4065544512 + ... + 4065557698.
It is an arithmetic number, because the mean of its divisors is an integer number (666407628432).
Almost surely, 253612422421635 is an apocalyptic number.
53612422421635 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53612422421635 is a deficient number, since it is larger than the sum of its proper divisors (31687754017661).
53612422421635 is a wasteful number, since it uses less digits than its factorization.
53612422421635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15901.
The product of its digits is 2073600, while the sum is 46.
It can be divided in two parts, 5361242 and 2421635, that added together give a palindrome (7782877).
The spelling of 53612422421635 in words is "fifty-three trillion, six hundred twelve billion, four hundred twenty-two million, four hundred twenty-one thousand, six hundred thirty-five".
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