Search a number
-
+
536241365047 is a prime number
BaseRepresentation
bin1111100110110100111…
…10011110000000110111
31220021010120201210220001
413303122132132000313
532241210242140142
61050202413252131
753512363252633
oct7633236360067
91807116653801
10536241365047
111974672a8463
1287b16194047
133b74b5b9b8b
141bd50549dc3
15de376705b7
hex7cda79e037

536241365047 has 2 divisors, whose sum is σ = 536241365048. Its totient is φ = 536241365046.

The previous prime is 536241365039. The next prime is 536241365069. The reversal of 536241365047 is 740563142635.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 536241365047 - 23 = 536241365039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 536241364988 and 536241365006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (536241365027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268120682523 + 268120682524.

It is an arithmetic number, because the mean of its divisors is an integer number (268120682524).

Almost surely, 2536241365047 is an apocalyptic number.

536241365047 is a deficient number, since it is larger than the sum of its proper divisors (1).

536241365047 is an equidigital number, since it uses as much as digits as its factorization.

536241365047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1814400, while the sum is 46.

The spelling of 536241365047 in words is "five hundred thirty-six billion, two hundred forty-one million, three hundred sixty-five thousand, forty-seven".