Base | Representation |
---|---|
bin | 110001111100110110… |
… | …100101011010010110 |
3 | 12010102212101022010012 |
4 | 301330312211122112 |
5 | 1334320334310400 |
6 | 40350025000222 |
7 | 3606051645233 |
oct | 617466453226 |
9 | 163385338105 |
10 | 53634291350 |
11 | 20823182a22 |
12 | a48a023072 |
13 | 5099998193 |
14 | 284b28878a |
15 | 15dd97bd35 |
hex | c7cda5696 |
53634291350 has 24 divisors (see below), whose sum is σ = 100008596808. Its totient is φ = 21400208000.
The previous prime is 53634291349. The next prime is 53634291397. The reversal of 53634291350 is 5319243635.
It is a hoax number, since the sum of its digits (41) coincides with the sum of the digits of its distinct prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 53634291298 and 53634291307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1317464 + ... + 1357563.
It is an arithmetic number, because the mean of its divisors is an integer number (4167024867).
Almost surely, 253634291350 is an apocalyptic number.
53634291350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53634291350 is a deficient number, since it is larger than the sum of its proper divisors (46374305458).
53634291350 is a wasteful number, since it uses less digits than its factorization.
53634291350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2675440 (or 2675435 counting only the distinct ones).
The product of its (nonzero) digits is 291600, while the sum is 41.
The spelling of 53634291350 in words is "fifty-three billion, six hundred thirty-four million, two hundred ninety-one thousand, three hundred fifty".
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