Base | Representation |
---|---|
bin | 110010000000110100… |
… | …000011111101010111 |
3 | 12010121111102012000200 |
4 | 302000310003331113 |
5 | 1334434342121103 |
6 | 40400401111543 |
7 | 3610516515000 |
oct | 620064037527 |
9 | 163544365020 |
10 | 53700738903 |
11 | 20857737a59 |
12 | a4a83285b3 |
13 | 50aa691a66 |
14 | 28560241a7 |
15 | 15e47050a3 |
hex | c80d03f57 |
53700738903 has 24 divisors (see below), whose sum is σ = 90458004000. Its totient is φ = 30686134752.
The previous prime is 53700738887. The next prime is 53700738979. The reversal of 53700738903 is 30983700735.
It is not a de Polignac number, because 53700738903 - 24 = 53700738887 is a prime.
It is a super-3 number, since 3×537007389033 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53700838903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8694798 + ... + 8700971.
It is an arithmetic number, because the mean of its divisors is an integer number (3769083500).
Almost surely, 253700738903 is an apocalyptic number.
53700738903 is a deficient number, since it is larger than the sum of its proper divisors (36757265097).
53700738903 is a wasteful number, since it uses less digits than its factorization.
53700738903 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17395796 (or 17395779 counting only the distinct ones).
The product of its (nonzero) digits is 476280, while the sum is 45.
The spelling of 53700738903 in words is "fifty-three billion, seven hundred million, seven hundred thirty-eight thousand, nine hundred three".
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