Base | Representation |
---|---|
bin | 100111000101011001100… |
… | …0010001011110111011011 |
3 | 201000112022220100120220000 |
4 | 1032022303002023313123 |
5 | 1201002231440031210 |
6 | 15231421504104043 |
7 | 1063044023360553 |
oct | 116126302136733 |
9 | 21015286316800 |
10 | 5371712814555 |
11 | 179114893084a |
12 | 7290a7905023 |
13 | 2cc720152749 |
14 | 147dc6ba0163 |
15 | 94ae5a76ac0 |
hex | 4e2b308bddb |
5371712814555 has 40 divisors (see below), whose sum is σ = 9653306091264. Its totient is φ = 2857768992000.
The previous prime is 5371712814553. The next prime is 5371712814557. The reversal of 5371712814555 is 5554182171735.
5371712814555 is a `hidden beast` number, since 5 + 3 + 7 + 1 + 7 + 1 + 2 + 81 + 4 + 555 = 666.
It is an interprime number because it is at equal distance from previous prime (5371712814553) and next prime (5371712814557).
It is not a de Polignac number, because 5371712814555 - 21 = 5371712814553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5371712814553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 16375611 + ... + 16700420.
Almost surely, 25371712814555 is an apocalyptic number.
5371712814555 is a deficient number, since it is larger than the sum of its proper divisors (4281593276709).
5371712814555 is a wasteful number, since it uses less digits than its factorization.
5371712814555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33076449 (or 33076440 counting only the distinct ones).
The product of its digits is 5880000, while the sum is 54.
The spelling of 5371712814555 in words is "five trillion, three hundred seventy-one billion, seven hundred twelve million, eight hundred fourteen thousand, five hundred fifty-five".
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