Base | Representation |
---|---|
bin | 100111000111011111110… |
… | …1010111111001100010111 |
3 | 201000221222000001101201021 |
4 | 1032032333222333030113 |
5 | 1201040444232220224 |
6 | 15233445024342011 |
7 | 1063263511223011 |
oct | 116167752771427 |
9 | 21027860041637 |
10 | 5376219804439 |
11 | 1793050a15a80 |
12 | 729b45174907 |
13 | 2ccc8ab05973 |
14 | 1482d35a91b1 |
15 | 94cab5961e4 |
hex | 4e3bfabf317 |
5376219804439 has 4 divisors (see below), whose sum is σ = 5864967059400. Its totient is φ = 4887472549480.
The previous prime is 5376219804437. The next prime is 5376219804451. The reversal of 5376219804439 is 9344089126735.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5376219804439 - 21 = 5376219804437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5376219804433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244373627464 + ... + 244373627485.
It is an arithmetic number, because the mean of its divisors is an integer number (1466241764850).
It is a 2-persistent number, because it is pandigital, and so is 2⋅5376219804439 = 10752439608878, but 3⋅5376219804439 = 16128659413317 is not.
Almost surely, 25376219804439 is an apocalyptic number.
5376219804439 is a deficient number, since it is larger than the sum of its proper divisors (488747254961).
5376219804439 is a wasteful number, since it uses less digits than its factorization.
5376219804439 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 488747254960.
The product of its (nonzero) digits is 39191040, while the sum is 61.
The spelling of 5376219804439 in words is "five trillion, three hundred seventy-six billion, two hundred nineteen million, eight hundred four thousand, four hundred thirty-nine".
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