Base | Representation |
---|---|
bin | 110010000110011111… |
… | …111100101010100101 |
3 | 12010212010220112020201 |
4 | 302012133330222211 |
5 | 1340133302120240 |
6 | 40414045430501 |
7 | 3613055361352 |
oct | 620637745245 |
9 | 163763815221 |
10 | 53796129445 |
11 | 208a6570313 |
12 | a51426b431 |
13 | 50c4380476 |
14 | 2864975629 |
15 | 15ecc98d9a |
hex | c867fcaa5 |
53796129445 has 8 divisors (see below), whose sum is σ = 65194517880. Its totient is φ = 42610795200.
The previous prime is 53796129437. The next prime is 53796129449. The reversal of 53796129445 is 54492169735.
It can be written as a sum of positive squares in 4 ways, for example, as 7267051009 + 46529078436 = 85247^2 + 215706^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53796129445 - 23 = 53796129437 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53796129449) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53262990 + ... + 53263999.
It is an arithmetic number, because the mean of its divisors is an integer number (8149314735).
Almost surely, 253796129445 is an apocalyptic number.
It is an amenable number.
53796129445 is a deficient number, since it is larger than the sum of its proper divisors (11398388435).
53796129445 is a wasteful number, since it uses less digits than its factorization.
53796129445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106527095.
The product of its digits is 8164800, while the sum is 55.
The spelling of 53796129445 in words is "fifty-three billion, seven hundred ninety-six million, one hundred twenty-nine thousand, four hundred forty-five".
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