5381227743 has 4 divisors (see below), whose sum is σ = 7174970328. Its totient is φ = 3587485160.

The previous prime is 5381227741. The next prime is 5381227771. The reversal of 5381227743 is 3477221835.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5381227743 - 2¹ = 5381227741 is a prime.

It is a super-2 number, since 2×5381227743² = 57915224044065748098, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5381227695 and 5381227704.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5381227741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 896871288 + ... + 896871293.

It is an arithmetic number, because the mean of its divisors is an integer number (1793742582).

Almost surely, 2^5381227743 is an apocalyptic number.

5381227743 is a deficient number, since it is larger than the sum of its proper divisors (1793742585).

5381227743 is a wasteful number, since it uses less digits than its factorization.

5381227743 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1793742584.

The product of its digits is 282240, while the sum is 42.

The square root of 5381227743 is about 73356.8520521430. The cubic root of 5381227743 is about 1752.3753043512.

The spelling of 5381227743 in words is "five billion, three hundred eighty-one million, two hundred twenty-seven thousand, seven hundred forty-three".