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53917332480001 is a prime number
BaseRepresentation
bin11000100001001100110110…
…11100110010000000000001
321001220110001121022211120001
430100212123130302000001
524031340144103330001
6310401140335320001
714233253522204344
oct1420463334620001
9231813047284501
1053917332480001
11161a82376213a1
126069659680001
1324114c8862bb3
14d458817d245b
156377a8380001
hex31099b732001

53917332480001 has 2 divisors, whose sum is σ = 53917332480002. Its totient is φ = 53917332480000.

The previous prime is 53917332479999. The next prime is 53917332480043. The reversal of 53917332480001 is 10008423371935.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51597270399376 + 2320062080625 = 7183124^2 + 1523175^2 .

It is a cyclic number.

It is not a de Polignac number, because 53917332480001 - 21 = 53917332479999 is a prime.

Together with 53917332479999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53917332480071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26958666240000 + 26958666240001.

It is an arithmetic number, because the mean of its divisors is an integer number (26958666240001).

Almost surely, 253917332480001 is an apocalyptic number.

It is an amenable number.

53917332480001 is a deficient number, since it is larger than the sum of its proper divisors (1).

53917332480001 is an equidigital number, since it uses as much as digits as its factorization.

53917332480001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 46.

The spelling of 53917332480001 in words is "fifty-three trillion, nine hundred seventeen billion, three hundred thirty-two million, four hundred eighty thousand, one".