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53942873400 = 233452132171961
BaseRepresentation
bin110010001111001111…
…101110110100111000
312011020101000220010000
4302033033232310320
51340433333422100
640440410553000
73616516600323
oct621717566470
9164211026100
1053942873400
1120971389209
12a555438760
1351188ac300
14287a2537ba
15160aad3900
hexc8f3eed38

53942873400 has 1440 divisors, whose sum is σ = 229817768400. Its totient is φ = 11645337600.

The previous prime is 53942873363. The next prime is 53942873431. The reversal of 53942873400 is 437824935.

53942873400 is a `hidden beast` number, since 539 + 4 + 2 + 8 + 73 + 40 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 359 ways as a sum of consecutive naturals, for example, 884309370 + ... + 884309430.

Almost surely, 253942873400 is an apocalyptic number.

53942873400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53942873400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (114908884200).

53942873400 is an abundant number, since it is smaller than the sum of its proper divisors (175874895000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53942873400 is a wasteful number, since it uses less digits than its factorization.

53942873400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151 (or 120 counting only the distinct ones).

The product of its (nonzero) digits is 725760, while the sum is 45.

The spelling of 53942873400 in words is "fifty-three billion, nine hundred forty-two million, eight hundred seventy-three thousand, four hundred".