Base | Representation |
---|---|
bin | 100111010011001011100… |
… | …1110101100010011000110 |
3 | 201010100201122202101102220 |
4 | 1032212113032230103012 |
5 | 1201443341120232100 |
6 | 15253154510113210 |
7 | 1065142344563325 |
oct | 116462716542306 |
9 | 21110648671386 |
10 | 5401311102150 |
11 | 17a275733a357 |
12 | 7329881ab806 |
13 | 3024592269a2 |
14 | 1495d3b1a0bc |
15 | 9577929eaa0 |
hex | 4e9973ac4c6 |
5401311102150 has 24 divisors (see below), whose sum is σ = 13395251533704. Its totient is φ = 1440349627200.
The previous prime is 5401311102029. The next prime is 5401311102181. The reversal of 5401311102150 is 512011131045.
It is a self number, because there is not a number n which added to its sum of digits gives 5401311102150.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18004370191 + ... + 18004370490.
It is an arithmetic number, because the mean of its divisors is an integer number (558135480571).
Almost surely, 25401311102150 is an apocalyptic number.
5401311102150 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5401311102150 is an abundant number, since it is smaller than the sum of its proper divisors (7993940431554).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5401311102150 is a wasteful number, since it uses less digits than its factorization.
5401311102150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36008740696 (or 36008740691 counting only the distinct ones).
The product of its (nonzero) digits is 600, while the sum is 24.
Adding to 5401311102150 its reverse (512011131045), we get a palindrome (5913322233195).
The spelling of 5401311102150 in words is "five trillion, four hundred one billion, three hundred eleven million, one hundred two thousand, one hundred fifty".
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