540403151 has 2 divisors, whose sum is σ = 540403152. Its totient is φ = 540403150.

The previous prime is 540403121. The next prime is 540403153. The reversal of 540403151 is 151304045.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 540403151 - 2¹⁴ = 540386767 is a prime.

It is a super-2 number, since 2×540403151² = 584071131221457602, which contains 22 as substring.

Together with 540403153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (540403153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270201575 + 270201576.

It is an arithmetic number, because the mean of its divisors is an integer number (270201576).

Almost surely, 2^540403151 is an apocalyptic number.

540403151 is a deficient number, since it is larger than the sum of its proper divisors (1).

540403151 is an equidigital number, since it uses as much as digits as its factorization.

540403151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 540403151 is about 23246.5728872021. The cubic root of 540403151 is about 814.5278864523.

Adding to 540403151 its reverse (151304045), we get a palindrome (691707196).

The spelling of 540403151 in words is "five hundred forty million, four hundred three thousand, one hundred fifty-one".