Base | Representation |
---|---|
bin | 1010000100010101… |
… | …11011111100000111 |
3 | 111221200201002010122 |
4 | 11002022323330013 |
5 | 42032203134003 |
6 | 2252202412155 |
7 | 250641564653 |
oct | 50212737407 |
9 | 14850632118 |
10 | 5405130503 |
11 | 2324067603 |
12 | 106a20105b |
13 | 681a78496 |
14 | 393bdda63 |
15 | 2197d0238 |
hex | 1422bbf07 |
5405130503 has 2 divisors, whose sum is σ = 5405130504. Its totient is φ = 5405130502.
The previous prime is 5405130427. The next prime is 5405130589. The reversal of 5405130503 is 3050315045.
5405130503 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5405130503 - 212 = 5405126407 is a prime.
It is a super-2 number, since 2×54051305032 = 58430871508922066018, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5405130593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2702565251 + 2702565252.
It is an arithmetic number, because the mean of its divisors is an integer number (2702565252).
Almost surely, 25405130503 is an apocalyptic number.
5405130503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5405130503 is an equidigital number, since it uses as much as digits as its factorization.
5405130503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 26.
The square root of 5405130503 is about 73519.5926471305. The cubic root of 5405130503 is about 1754.9660849013.
Adding to 5405130503 its reverse (3050315045), we get a palindrome (8455445548).
The spelling of 5405130503 in words is "five billion, four hundred five million, one hundred thirty thousand, five hundred three".
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