Base | Representation |
---|---|
bin | 110010011110011101… |
… | …100000101111101111 |
3 | 12011220011100222112001 |
4 | 302132131200233233 |
5 | 1341444211101413 |
6 | 40522010153131 |
7 | 3626036423404 |
oct | 623635405757 |
9 | 164804328461 |
10 | 54198143983 |
11 | 20a92491835 |
12 | a606a227a7 |
13 | 51597489a9 |
14 | 28a21022ab |
15 | 16232094dd |
hex | c9e760bef |
54198143983 has 2 divisors, whose sum is σ = 54198143984. Its totient is φ = 54198143982.
The previous prime is 54198143981. The next prime is 54198144031. The reversal of 54198143983 is 38934189145.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54198143983 - 21 = 54198143981 is a prime.
It is a super-2 number, since 2×541981439832 (a number of 22 digits) contains 22 as substring.
Together with 54198143981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54198143981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27099071991 + 27099071992.
It is an arithmetic number, because the mean of its divisors is an integer number (27099071992).
Almost surely, 254198143983 is an apocalyptic number.
54198143983 is a deficient number, since it is larger than the sum of its proper divisors (1).
54198143983 is an equidigital number, since it uses as much as digits as its factorization.
54198143983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3732480, while the sum is 55.
The spelling of 54198143983 in words is "fifty-four billion, one hundred ninety-eight million, one hundred forty-three thousand, nine hundred eighty-three".
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