542001401 has 2 divisors, whose sum is σ = 542001402. Its totient is φ = 542001400.

The previous prime is 542001379. The next prime is 542001403. The reversal of 542001401 is 104100245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 540609001 + 1392400 = 23251^2 + 1180^2 .

It is a cyclic number.

It is not a de Polignac number, because 542001401 - 2¹⁰ = 542000377 is a prime.

Together with 542001403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 542001401.

It is not a weakly prime, because it can be changed into another prime (542001403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271000700 + 271000701.

It is an arithmetic number, because the mean of its divisors is an integer number (271000701).

Almost surely, 2^542001401 is an apocalyptic number.

It is an amenable number.

542001401 is a deficient number, since it is larger than the sum of its proper divisors (1).

542001401 is an equidigital number, since it uses as much as digits as its factorization.

542001401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 17.

The square root of 542001401 is about 23280.9235426776. The cubic root of 542001401 is about 815.3300887301.

Adding to 542001401 its reverse (104100245), we get a palindrome (646101646).

The spelling of 542001401 in words is "five hundred forty-two million, one thousand, four hundred one".