Base | Representation |
---|---|
bin | 11000101010010011010101… |
… | …11011011000100001011101 |
3 | 21010000100020111110012111111 |
4 | 30111021222323120201131 |
5 | 24102001121030444013 |
6 | 311200535211222021 |
7 | 14264664135061015 |
oct | 1425115273304135 |
9 | 233010214405444 |
10 | 54230051031133 |
11 | 1630892103a37a |
12 | 60ba192447911 |
13 | 2434b4465c4b3 |
14 | d56a69b58c45 |
15 | 6409ac3e873d |
hex | 31526aed885d |
54230051031133 has 2 divisors, whose sum is σ = 54230051031134. Its totient is φ = 54230051031132.
The previous prime is 54230051031119. The next prime is 54230051031157. The reversal of 54230051031133 is 33113015003245.
It is a happy number.
54230051031133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46496551670244 + 7733499360889 = 6818838^2 + 2780917^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54230051031133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54230051031095 and 54230051031104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54230051031103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27115025515566 + 27115025515567.
It is an arithmetic number, because the mean of its divisors is an integer number (27115025515567).
Almost surely, 254230051031133 is an apocalyptic number.
It is an amenable number.
54230051031133 is a deficient number, since it is larger than the sum of its proper divisors (1).
54230051031133 is an equidigital number, since it uses as much as digits as its factorization.
54230051031133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 54230051031133 its reverse (33113015003245), we get a palindrome (87343066034378).
The spelling of 54230051031133 in words is "fifty-four trillion, two hundred thirty billion, fifty-one million, thirty-one thousand, one hundred thirty-three".
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