Base | Representation |
---|---|
bin | 111101101111111110010100… |
… | …0101001011101001101011000 |
3 | 2122020011010022222022212001101 |
4 | 1323133330220221131031120 |
5 | 1032143023202031011412 |
6 | 5203110004511401144 |
7 | 222256443330121024 |
oct | 17337745051351530 |
9 | 2566133288285041 |
10 | 543155131110232 |
11 | 14807a885539833 |
12 | 50b0312a5231b4 |
13 | 1a40c4030b32a4 |
14 | 981abc484d384 |
15 | 42bdaa1142457 |
hex | 1edff28a5d358 |
543155131110232 has 64 divisors (see below), whose sum is σ = 1032560406540000. Its totient is φ = 267821771965440.
The previous prime is 543155131110223. The next prime is 543155131110233. The reversal of 543155131110232 is 232011131551345.
It is a junction number, because it is equal to n+sod(n) for n = 543155131110191 and 543155131110200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (543155131110233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6987586807 + ... + 6987664537.
Almost surely, 2543155131110232 is an apocalyptic number.
It is an amenable number.
543155131110232 is a deficient number, since it is larger than the sum of its proper divisors (489405275429768).
543155131110232 is a wasteful number, since it uses less digits than its factorization.
543155131110232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103444 (or 103440 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 37.
Adding to 543155131110232 its reverse (232011131551345), we get a palindrome (775166262661577).
The spelling of 543155131110232 in words is "five hundred forty-three trillion, one hundred fifty-five billion, one hundred thirty-one million, one hundred ten thousand, two hundred thirty-two".
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