543311113345 has 160 divisors (see below), whose sum is σ = 940646609280. Its totient is φ = 296162334720.

The previous prime is 543311113297. The next prime is 543311113393.

543311113345 is nontrivially palindromic in base 10.

It is an interprime number because it is at equal distance from previous prime (543311113297) and next prime (543311113393).

It is not a de Polignac number, because 543311113345 - 2⁹ = 543311112833 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 543311113345.

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 32609257 + ... + 32625913.

It is an arithmetic number, because the mean of its divisors is an integer number (5879041308).

Almost surely, 2^543311113345 is an apocalyptic number.

543311113345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

It is an amenable number.

543311113345 is a deficient number, since it is larger than the sum of its proper divisors (397335495935).

543311113345 is a wasteful number, since it uses less digits than its factorization.

543311113345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16733 (or 16712 counting only the distinct ones).

The product of its digits is 32400, while the sum is 34.

It can be divided in two parts, 543311 and 113345, that added together give a palindrome (656656).

The spelling of 543311113345 in words is "five hundred forty-three billion, three hundred eleven million, one hundred thirteen thousand, three hundred forty-five".