544113131 has 2 divisors, whose sum is σ = 544113132. Its totient is φ = 544113130.

The previous prime is 544113121. The next prime is 544113133. The reversal of 544113131 is 131311445.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-544113131 is a prime.

It is a super-2 number, since 2×544113131² = 592118198653246322, which contains 22 as substring.

Together with 544113133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 544113097 and 544113106.

It is not a weakly prime, because it can be changed into another prime (544113133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272056565 + 272056566.

It is an arithmetic number, because the mean of its divisors is an integer number (272056566).

Almost surely, 2^544113131 is an apocalyptic number.

544113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

544113131 is an equidigital number, since it uses as much as digits as its factorization.

544113131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 23.

The square root of 544113131 is about 23326.2326791104. The cubic root of 544113131 is about 816.3876049077.

Adding to 544113131 its reverse (131311445), we get a palindrome (675424576).

The spelling of 544113131 in words is "five hundred forty-four million, one hundred thirteen thousand, one hundred thirty-one".