Base | Representation |
---|---|
bin | 11000101111111010110011… |
… | …00011010010111011111101 |
3 | 21010200210100202010121122120 |
4 | 30113331121203102323331 |
5 | 24113131332424014240 |
6 | 311425332441233153 |
7 | 14314635331033320 |
oct | 1427753143227375 |
9 | 233623322117576 |
10 | 54423033032445 |
11 | 16382751383260 |
12 | 612b66b7927b9 |
13 | 244a0baa1320c |
14 | d62135b567b7 |
15 | 645a0469aad0 |
hex | 317f598d2efd |
54423033032445 has 64 divisors (see below), whose sum is σ = 108564351307776. Its totient is φ = 22617155566080.
The previous prime is 54423033032443. The next prime is 54423033032447.
54423033032445 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (54423033032443) and next prime (54423033032447).
It is not a de Polignac number, because 54423033032445 - 21 = 54423033032443 is a prime.
It is a super-2 number, since 2×544230330324452 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54423033032397 and 54423033032406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54423033032443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 235108152 + ... + 235339518.
It is an arithmetic number, because the mean of its divisors is an integer number (1696317989184).
Almost surely, 254423033032445 is an apocalyptic number.
54423033032445 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54423033032445 is a deficient number, since it is larger than the sum of its proper divisors (54141318275331).
54423033032445 is a wasteful number, since it uses less digits than its factorization.
54423033032445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 435050.
The product of its (nonzero) digits is 2073600, while the sum is 42.
It can be divided in two parts, 5442303 and 3032445, that added together give a palindrome (8474748).
The spelling of 54423033032445 in words is "fifty-four trillion, four hundred twenty-three billion, thirty-three million, thirty-two thousand, four hundred forty-five".
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