Base | Representation |
---|---|
bin | 11000110110010010111001… |
… | …10111111010110101100111 |
3 | 21011110201220010200120212002 |
4 | 30123021130313322311213 |
5 | 24130224041304240003 |
6 | 312114125434515515 |
7 | 14336522654303321 |
oct | 1433113467726547 |
9 | 234421803616762 |
10 | 54642132102503 |
11 | 16457664066480 |
12 | 6166017595b9b |
13 | 2464966b7927a |
14 | d6c99c600611 |
15 | 64b579728a88 |
hex | 31b25cdfad67 |
54642132102503 has 8 divisors (see below), whose sum is σ = 59647254771456. Its totient is φ = 49643285452600.
The previous prime is 54642132102463. The next prime is 54642132102521. The reversal of 54642132102503 is 30520123124645.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54642132102503 - 28 = 54642132102247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54642132102563) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1568986553 + ... + 1569021378.
It is an arithmetic number, because the mean of its divisors is an integer number (7455906846432).
Almost surely, 254642132102503 is an apocalyptic number.
54642132102503 is a deficient number, since it is larger than the sum of its proper divisors (5005122668953).
54642132102503 is a wasteful number, since it uses less digits than its factorization.
54642132102503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3138009525.
The product of its (nonzero) digits is 172800, while the sum is 38.
The spelling of 54642132102503 in words is "fifty-four trillion, six hundred forty-two billion, one hundred thirty-two million, one hundred two thousand, five hundred three".
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