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550121200143 = 31400913089709
BaseRepresentation
bin10000000000101011100…
…01110101101000001111
31221120221220002111012120
420000111301311220033
533003122011401033
61100415554304023
754513342022314
oct10002561655017
91846856074176
10550121200143
111a233a091a59
128a74a588013
133cb51044a58
141c8a9aa2d0b
15e49ae691b3
hex8015c75a0f

550121200143 has 8 divisors (see below), whose sum is σ = 733547348400. Its totient is φ = 366721259328.

The previous prime is 550121200103. The next prime is 550121200199. The reversal of 550121200143 is 341002121055.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 550121200143 - 210 = 550121199119 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550121200103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6502828 + ... + 6586881.

It is an arithmetic number, because the mean of its divisors is an integer number (91693418550).

Almost surely, 2550121200143 is an apocalyptic number.

550121200143 is a deficient number, since it is larger than the sum of its proper divisors (183426148257).

550121200143 is a wasteful number, since it uses less digits than its factorization.

550121200143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13103721.

The product of its (nonzero) digits is 1200, while the sum is 24.

Adding to 550121200143 its reverse (341002121055), we get a palindrome (891123321198).

The spelling of 550121200143 in words is "five hundred fifty billion, one hundred twenty-one million, two hundred thousand, one hundred forty-three".

Divisors: 1 3 14009 42027 13089709 39269127 183373733381 550121200143