Base | Representation |
---|---|
bin | 110011001111001010… |
… | …110110000011011111 |
3 | 12021000010001112122002 |
4 | 303033022312003133 |
5 | 1400132411142421 |
6 | 41135041312515 |
7 | 3655221424043 |
oct | 631712660337 |
9 | 167003045562 |
10 | 55015334111 |
11 | 213717a3881 |
12 | a7b463573b |
13 | 5259b3a04a |
14 | 293c864023 |
15 | 166ed29b0b |
hex | ccf2b60df |
55015334111 has 4 divisors (see below), whose sum is σ = 55379674224. Its totient is φ = 54650994000.
The previous prime is 55015334053. The next prime is 55015334117. The reversal of 55015334111 is 11143351055.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11143351055 = 5 ⋅2228670211.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55015334111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55015334117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182169830 + ... + 182170131.
It is an arithmetic number, because the mean of its divisors is an integer number (13844918556).
Almost surely, 255015334111 is an apocalyptic number.
55015334111 is a deficient number, since it is larger than the sum of its proper divisors (364340113).
55015334111 is a wasteful number, since it uses less digits than its factorization.
55015334111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 364340112.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 55015334111 its reverse (11143351055), we get a palindrome (66158685166).
The spelling of 55015334111 in words is "fifty-five billion, fifteen million, three hundred thirty-four thousand, one hundred eleven".
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