Base | Representation |
---|---|
bin | 10000000000110110100… |
… | …01101111110111110111 |
3 | 1221121012022200022221102 |
4 | 20000123101233313313 |
5 | 33003314120420010 |
6 | 1100433051440315 |
7 | 54515542112066 |
oct | 10003321576767 |
9 | 1847168608842 |
10 | 550213451255 |
11 | 1a2387170646 |
12 | 8a77545609b |
13 | 3cb671a4500 |
14 | 1c8b80381dd |
15 | e4a40dcba5 |
hex | 801b46fdf7 |
550213451255 has 24 divisors (see below), whose sum is σ = 715512314880. Its totient is φ = 405992995200.
The previous prime is 550213451231. The next prime is 550213451257. The reversal of 550213451255 is 552154312055.
It is not a de Polignac number, because 550213451255 - 222 = 550209256951 is a prime.
It is a super-2 number, since 2×5502134512552 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550213451257) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 826205 + ... + 1335305.
It is an arithmetic number, because the mean of its divisors is an integer number (29813013120).
Almost surely, 2550213451255 is an apocalyptic number.
550213451255 is a deficient number, since it is larger than the sum of its proper divisors (165298863625).
550213451255 is a wasteful number, since it uses less digits than its factorization.
550213451255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 510411 (or 510398 counting only the distinct ones).
The product of its (nonzero) digits is 150000, while the sum is 38.
The spelling of 550213451255 in words is "five hundred fifty billion, two hundred thirteen million, four hundred fifty-one thousand, two hundred fifty-five".
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