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550230011141 is a prime number
BaseRepresentation
bin10000000000111000100…
…00111010110100000101
31221121020110211122211112
420000130100322310011
533003332340324031
61100434442414405
754516132632456
oct10003420726405
91847213748745
10550230011141
111a23955512a8
128a77ab01405
133cb6a751b65
141c8ba30912d
15e4a57ae62b
hex801c43ad05

550230011141 has 2 divisors, whose sum is σ = 550230011142. Its totient is φ = 550230011140.

The previous prime is 550230011113. The next prime is 550230011143. The reversal of 550230011141 is 141110032055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 493548400900 + 56681610241 = 702530^2 + 238079^2 .

It is a cyclic number.

It is not a de Polignac number, because 550230011141 - 210 = 550230010117 is a prime.

Together with 550230011143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550230011143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275115005570 + 275115005571.

It is an arithmetic number, because the mean of its divisors is an integer number (275115005571).

Almost surely, 2550230011141 is an apocalyptic number.

It is an amenable number.

550230011141 is a deficient number, since it is larger than the sum of its proper divisors (1).

550230011141 is an equidigital number, since it uses as much as digits as its factorization.

550230011141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 550230011141 its reverse (141110032055), we get a palindrome (691340043196).

The spelling of 550230011141 in words is "five hundred fifty billion, two hundred thirty million, eleven thousand, one hundred forty-one".