Base | Representation |
---|---|
bin | 101000000010010100110… |
… | …0111000010001001001111 |
3 | 201111001001020212110012201 |
4 | 1100010221213002021033 |
5 | 1210123211102020211 |
6 | 15411500452542331 |
7 | 1105355230342351 |
oct | 120045147021117 |
9 | 21431036773181 |
10 | 5502551204431 |
11 | 1831689781676 |
12 | 74a5213219a7 |
13 | 30bb7192bb58 |
14 | 1504797490d1 |
15 | 982022e70c1 |
hex | 501299c224f |
5502551204431 has 2 divisors, whose sum is σ = 5502551204432. Its totient is φ = 5502551204430.
The previous prime is 5502551204383. The next prime is 5502551204459. The reversal of 5502551204431 is 1344021552055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5502551204431 - 211 = 5502551202383 is a prime.
It is a super-2 number, since 2×55025512044312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5502551204131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751275602215 + 2751275602216.
It is an arithmetic number, because the mean of its divisors is an integer number (2751275602216).
Almost surely, 25502551204431 is an apocalyptic number.
5502551204431 is a deficient number, since it is larger than the sum of its proper divisors (1).
5502551204431 is an equidigital number, since it uses as much as digits as its factorization.
5502551204431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120000, while the sum is 37.
Adding to 5502551204431 its reverse (1344021552055), we get a palindrome (6846572756486).
The spelling of 5502551204431 in words is "five trillion, five hundred two billion, five hundred fifty-one million, two hundred four thousand, four hundred thirty-one".
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