550433004151 has 4 divisors (see below), whose sum is σ = 569413452600. Its totient is φ = 531452555704.

The previous prime is 550433004137. The next prime is 550433004167. The reversal of 550433004151 is 151400334055.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151400334055 = 5 ⋅30280066811.

It is a cyclic number.

It is not a de Polignac number, because 550433004151 - 2¹⁷ = 550432873079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550433004851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9490224181 + ... + 9490224238.

It is an arithmetic number, because the mean of its divisors is an integer number (142353363150).

Almost surely, 2^550433004151 is an apocalyptic number.

550433004151 is a deficient number, since it is larger than the sum of its proper divisors (18980448449).

550433004151 is a wasteful number, since it uses less digits than its factorization.

550433004151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18980448448.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 550433004151 in words is "five hundred fifty billion, four hundred thirty-three million, four thousand, one hundred fifty-one".