Search a number
-
+
550531111413 = 3183510370471
BaseRepresentation
bin10000000001011100011…
…01100001100111110101
31221122000110102010202110
420000232031201213311
533004441431031123
61100524400201233
754526450144023
oct10005615414765
91848013363673
10550531111413
111a252a5073a8
128a843909219
133cbb7c466ba
141c9082c7713
15e4c1e39493
hex802e3619f5

550531111413 has 4 divisors (see below), whose sum is σ = 734041481888. Its totient is φ = 367020740940.

The previous prime is 550531111411. The next prime is 550531111423. The reversal of 550531111413 is 314111135055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 550531111413 - 21 = 550531111411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550531111411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91755185233 + ... + 91755185238.

It is an arithmetic number, because the mean of its divisors is an integer number (183510370472).

Almost surely, 2550531111413 is an apocalyptic number.

It is an amenable number.

550531111413 is a deficient number, since it is larger than the sum of its proper divisors (183510370475).

550531111413 is a wasteful number, since it uses less digits than its factorization.

550531111413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183510370474.

The product of its (nonzero) digits is 4500, while the sum is 30.

Adding to 550531111413 its reverse (314111135055), we get a palindrome (864642246468).

The spelling of 550531111413 in words is "five hundred fifty billion, five hundred thirty-one million, one hundred eleven thousand, four hundred thirteen".

Divisors: 1 3 183510370471 550531111413