Base | Representation |
---|---|
bin | 110011010101000001… |
… | …110100010110110011 |
3 | 12021020222000112211100 |
4 | 303111001310112303 |
5 | 1400333042144110 |
6 | 41152512215443 |
7 | 3660524064252 |
oct | 632501642663 |
9 | 167228015740 |
10 | 55113631155 |
11 | 21412231900 |
12 | a82153a583 |
13 | 527430568b |
14 | 294b930799 |
15 | 1678794bc0 |
hex | cd50745b3 |
55113631155 has 72 divisors (see below), whose sum is σ = 105986842416. Its totient is φ = 26471744640.
The previous prime is 55113631127. The next prime is 55113631169.
55113631155 is a `hidden beast` number, since 5 + 5 + 1 + 1 + 3 + 631 + 15 + 5 = 666.
55113631155 is nontrivially palindromic in base 10.
55113631155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55113631155 - 25 = 55113631123 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 535317 + ... + 629913.
It is an arithmetic number, because the mean of its divisors is an integer number (1472039478).
Almost surely, 255113631155 is an apocalyptic number.
55113631155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55113631155 is a deficient number, since it is larger than the sum of its proper divisors (50873211261).
55113631155 is a wasteful number, since it uses less digits than its factorization.
55113631155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94737 (or 94723 counting only the distinct ones).
The product of its digits is 33750, while the sum is 36.
The spelling of 55113631155 in words is "fifty-five billion, one hundred thirteen million, six hundred thirty-one thousand, one hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •