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55124460320191 is a prime number
BaseRepresentation
bin11001000100010101010011…
…11000000011010110111111
321020011211212102022202002121
430202022221320003112333
524211124343320221231
6313123454422303411
714416416341433523
oct1442125170032677
9236154772282077
1055124460320191
11166231748392a9
1262235a6287b67
13249b2a2a94202
14d88076833d83
15658da8bd8311
hex3222a9e035bf

55124460320191 has 2 divisors, whose sum is σ = 55124460320192. Its totient is φ = 55124460320190.

The previous prime is 55124460320107. The next prime is 55124460320203. The reversal of 55124460320191 is 19102306442155.

It is a happy number.

55124460320191 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55124460320191 - 221 = 55124458223039 is a prime.

It is a super-2 number, since 2×551244603201912 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55124460320591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27562230160095 + 27562230160096.

It is an arithmetic number, because the mean of its divisors is an integer number (27562230160096).

Almost surely, 255124460320191 is an apocalyptic number.

55124460320191 is a deficient number, since it is larger than the sum of its proper divisors (1).

55124460320191 is an equidigital number, since it uses as much as digits as its factorization.

55124460320191 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 43.

The spelling of 55124460320191 in words is "fifty-five trillion, one hundred twenty-four billion, four hundred sixty million, three hundred twenty thousand, one hundred ninety-one".