Base | Representation |
---|---|
bin | 10000000010110111010… |
… | …00111110000010110111 |
3 | 1221200222120120100002220 |
4 | 20001123220332002313 |
5 | 33013022034433224 |
6 | 1101132144133423 |
7 | 54554363365116 |
oct | 10013350760267 |
9 | 1850876510086 |
10 | 551293280439 |
11 | 1a2890759260 |
12 | 8aa17007273 |
13 | 3cca9b120a5 |
14 | 1c97b605c7d |
15 | e518cdc279 |
hex | 805ba3e0b7 |
551293280439 has 16 divisors (see below), whose sum is σ = 813849513600. Its totient is φ = 329130315360.
The previous prime is 551293280431. The next prime is 551293280459. The reversal of 551293280439 is 934082392155.
It is a happy number.
It is not a de Polignac number, because 551293280439 - 23 = 551293280431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 551293280391 and 551293280400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (551293280431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 124668364 + ... + 124672785.
It is an arithmetic number, because the mean of its divisors is an integer number (50865594600).
Almost surely, 2551293280439 is an apocalyptic number.
551293280439 is a deficient number, since it is larger than the sum of its proper divisors (262556233161).
551293280439 is a wasteful number, since it uses less digits than its factorization.
551293280439 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 249341230.
The product of its (nonzero) digits is 2332800, while the sum is 51.
The spelling of 551293280439 in words is "five hundred fifty-one billion, two hundred ninety-three million, two hundred eighty thousand, four hundred thirty-nine".
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