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552114121411255 = 5138494063406327
BaseRepresentation
bin111110110001001010001011…
…0000101010000101010110111
32200101212121001102011010021211
41331202110112011100222313
51034331314210040130010
65234125420442022251
7224202633423160564
oct17542242605205267
92611777042133254
10552114121411255
1114aa14313a51057
1251b0b4ba1a7987
131a90c1a49689c0
149a4a674c1386b
1543c6b4e38c08a
hex1f62516150ab7

552114121411255 has 8 divisors (see below), whose sum is σ = 713501326131552. Its totient is φ = 407715043503648.

The previous prime is 552114121411253. The next prime is 552114121411289.

552114121411255 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 552114121411255 - 21 = 552114121411253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (552114121411253) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4247031703099 + ... + 4247031703228.

It is an arithmetic number, because the mean of its divisors is an integer number (89187665766444).

Almost surely, 2552114121411255 is an apocalyptic number.

552114121411255 is a deficient number, since it is larger than the sum of its proper divisors (161387204720297).

552114121411255 is a wasteful number, since it uses less digits than its factorization.

552114121411255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8494063406345.

The product of its digits is 80000, while the sum is 40.

The spelling of 552114121411255 in words is "five hundred fifty-two trillion, one hundred fourteen billion, one hundred twenty-one million, four hundred eleven thousand, two hundred fifty-five".

Divisors: 1 5 13 65 8494063406327 42470317031635 110422824282251 552114121411255