Base | Representation |
---|---|
bin | 10000000100110000101… |
… | …11111000111100000111 |
3 | 1221210121120212111011100 |
4 | 20002120113320330013 |
5 | 33022113411311010 |
6 | 1101421223311143 |
7 | 54621545231535 |
oct | 10023027707407 |
9 | 1853546774140 |
10 | 552312213255 |
11 | 1a32639335a0 |
12 | 8b0602ab4b3 |
13 | 4010cc4aa0a |
14 | 1ca36a81155 |
15 | e5784ad2c0 |
hex | 80985f8f07 |
552312213255 has 192 divisors, whose sum is σ = 1092211900416. Its totient is φ = 255830400000.
The previous prime is 552312213251. The next prime is 552312213307.
552312213255 is a `hidden beast` number, since 5 + 523 + 122 + 1 + 3 + 2 + 5 + 5 = 666.
552312213255 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 552312213255 - 22 = 552312213251 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (552312213251) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 234925330 + ... + 234927680.
It is an arithmetic number, because the mean of its divisors is an integer number (5688603648).
Almost surely, 2552312213255 is an apocalyptic number.
552312213255 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
552312213255 is a deficient number, since it is larger than the sum of its proper divisors (539899687161).
552312213255 is a wasteful number, since it uses less digits than its factorization.
552312213255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2638 (or 2635 counting only the distinct ones).
The product of its digits is 90000, while the sum is 36.
It can be divided in two parts, 552312 and 213255, that added together give a palindrome (765567).
The spelling of 552312213255 in words is "five hundred fifty-two billion, three hundred twelve million, two hundred thirteen thousand, two hundred fifty-five".
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