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554374657061 is a prime number
BaseRepresentation
bin10000001000100110100…
…11011111010000100101
31221222221022201111011222
420010103103133100211
533040324403011221
61102402020510125
755023630556331
oct10042323372045
91858838644158
10554374657061
111a4122050105
128b536b4b345
134037b319474
141cb909527c1
15e6495a79ab
hex81134df425

554374657061 has 2 divisors, whose sum is σ = 554374657062. Its totient is φ = 554374657060.

The previous prime is 554374657049. The next prime is 554374657063. The reversal of 554374657061 is 160756473455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 289799188900 + 264575468161 = 538330^2 + 514369^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-554374657061 is a prime.

Together with 554374657063, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 554374656994 and 554374657012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554374657063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277187328530 + 277187328531.

It is an arithmetic number, because the mean of its divisors is an integer number (277187328531).

Almost surely, 2554374657061 is an apocalyptic number.

It is an amenable number.

554374657061 is a deficient number, since it is larger than the sum of its proper divisors (1).

554374657061 is an equidigital number, since it uses as much as digits as its factorization.

554374657061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10584000, while the sum is 53.

The spelling of 554374657061 in words is "five hundred fifty-four billion, three hundred seventy-four million, six hundred fifty-seven thousand, sixty-one".