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5613441437 is a prime number
BaseRepresentation
bin1010011101001011…
…00101000110011101
3112111012200101000102
411032211211012131
542444020111222
62325003310445
7256051315322
oct51645450635
915435611012
105613441437
1124207066aa
121107b1b425
136b5c825a6
143b3746b49
1522cc2bd92
hex14e96519d

5613441437 has 2 divisors, whose sum is σ = 5613441438. Its totient is φ = 5613441436.

The previous prime is 5613441419. The next prime is 5613441439. The reversal of 5613441437 is 7341443165.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5254945081 + 358496356 = 72491^2 + 18934^2 .

It is a cyclic number.

It is not a de Polignac number, because 5613441437 - 212 = 5613437341 is a prime.

Together with 5613441439, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5613441437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5613441439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806720718 + 2806720719.

It is an arithmetic number, because the mean of its divisors is an integer number (2806720719).

Almost surely, 25613441437 is an apocalyptic number.

It is an amenable number.

5613441437 is a deficient number, since it is larger than the sum of its proper divisors (1).

5613441437 is an equidigital number, since it uses as much as digits as its factorization.

5613441437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 38.

The square root of 5613441437 is about 74922.9032873126. The cubic root of 5613441437 is about 1777.2276665362.

The spelling of 5613441437 in words is "five billion, six hundred thirteen million, four hundred forty-one thousand, four hundred thirty-seven".