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5640251712413 is a prime number
BaseRepresentation
bin101001000010011100100…
…1100110010001110011101
3201222012110211200000220212
41102010321030302032131
51214402213414244123
615555032412422205
71121331460344323
oct122047114621635
921865424600825
105640251712413
11188502106138a
12771150a77965
1331bb47c95c86
14156dbd7dbd13
159bab11e7878
hex5213933239d

5640251712413 has 2 divisors, whose sum is σ = 5640251712414. Its totient is φ = 5640251712412.

The previous prime is 5640251712367. The next prime is 5640251712439. The reversal of 5640251712413 is 3142171520465.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5420878445284 + 219373267129 = 2328278^2 + 468373^2 .

It is a cyclic number.

It is not a de Polignac number, because 5640251712413 - 26 = 5640251712349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5640251712113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2820125856206 + 2820125856207.

It is an arithmetic number, because the mean of its divisors is an integer number (2820125856207).

Almost surely, 25640251712413 is an apocalyptic number.

It is an amenable number.

5640251712413 is a deficient number, since it is larger than the sum of its proper divisors (1).

5640251712413 is an equidigital number, since it uses as much as digits as its factorization.

5640251712413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 5640251712413 in words is "five trillion, six hundred forty billion, two hundred fifty-one million, seven hundred twelve thousand, four hundred thirteen".