Base | Representation |
---|---|
bin | 1010110111110101… |
… | …01001111010000001 |
3 | 120001210110212200001 |
4 | 11123322221322001 |
5 | 43423242214303 |
6 | 2403112400001 |
7 | 264435163441 |
oct | 53372517201 |
9 | 16053425601 |
10 | 5837069953 |
11 | 2525968060 |
12 | 116a9a6001 |
13 | 7203c0760 |
14 | 3d531a121 |
15 | 2426a231d |
hex | 15bea9e81 |
5837069953 has 8 divisors (see below), whose sum is σ = 6857536896. Its totient is φ = 4898240400.
The previous prime is 5837069897. The next prime is 5837069957. The reversal of 5837069953 is 3599607385.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5837069953 - 213 = 5837061761 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5837069894 and 5837069903.
It is not an unprimeable number, because it can be changed into a prime (5837069957) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20409193 + ... + 20409478.
It is an arithmetic number, because the mean of its divisors is an integer number (857192112).
Almost surely, 25837069953 is an apocalyptic number.
It is an amenable number.
5837069953 is a deficient number, since it is larger than the sum of its proper divisors (1020466943).
5837069953 is a wasteful number, since it uses less digits than its factorization.
5837069953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40818695.
The product of its (nonzero) digits is 6123600, while the sum is 55.
The square root of 5837069953 is about 76400.7195843076. The cubic root of 5837069953 is about 1800.5214490277.
The spelling of 5837069953 in words is "five billion, eight hundred thirty-seven million, sixty-nine thousand, nine hundred fifty-three".
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