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59479497493 = 134575345961
BaseRepresentation
bin110111011001010000…
…010001101100010101
312200112020011112112121
4313121100101230111
51433303222404433
643154032015541
74203646246453
oct673120215425
9180466145477
1059479497493
11232526978a9
12b63b6915b1
1357bb977040
142c436c19d3
151831bd9c2d
hexdd9411b15

59479497493 has 4 divisors (see below), whose sum is σ = 64054843468. Its totient is φ = 54904151520.

The previous prime is 59479497487. The next prime is 59479497503. The reversal of 59479497493 is 39479497495.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6803280324 + 52676217169 = 82482^2 + 229513^2 .

It is a cyclic number.

It is not a de Polignac number, because 59479497493 - 217 = 59479366421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (59479497403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2287672968 + ... + 2287672993.

It is an arithmetic number, because the mean of its divisors is an integer number (16013710867).

Almost surely, 259479497493 is an apocalyptic number.

It is an amenable number.

59479497493 is a deficient number, since it is larger than the sum of its proper divisors (4575345975).

59479497493 is a wasteful number, since it uses less digits than its factorization.

59479497493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4575345974.

The product of its digits is 308629440, while the sum is 70.

The spelling of 59479497493 in words is "fifty-nine billion, four hundred seventy-nine million, four hundred ninety-seven thousand, four hundred ninety-three".

Divisors: 1 13 4575345961 59479497493