Base | Representation |
---|---|
bin | 101011100111001001100… |
… | …0101010000110111101101 |
3 | 210020000102110202201112121 |
4 | 1113032103011100313231 |
5 | 1241201100413232433 |
6 | 20425325314232541 |
7 | 1156022410635463 |
oct | 127162305206755 |
9 | 23200373681477 |
10 | 5993947008493 |
11 | 1a01022908334 |
12 | 809800885751 |
13 | 3462c42cc112 |
14 | 16a173d48833 |
15 | a5db2883c2d |
hex | 57393150ded |
5993947008493 has 2 divisors, whose sum is σ = 5993947008494. Its totient is φ = 5993947008492.
The previous prime is 5993947008473. The next prime is 5993947008521. The reversal of 5993947008493 is 3948007493995.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3379118944644 + 2614828063849 = 1838238^2 + 1617043^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5993947008493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5993947008403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2996973504246 + 2996973504247.
It is an arithmetic number, because the mean of its divisors is an integer number (2996973504247).
Almost surely, 25993947008493 is an apocalyptic number.
It is an amenable number.
5993947008493 is a deficient number, since it is larger than the sum of its proper divisors (1).
5993947008493 is an equidigital number, since it uses as much as digits as its factorization.
5993947008493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 264539520, while the sum is 70.
The spelling of 5993947008493 in words is "five trillion, nine hundred ninety-three billion, nine hundred forty-seven million, eight thousand, four hundred ninety-three".
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