Base | Representation |
---|---|
bin | 101100100111001010111… |
… | …0001111111110110010000 |
3 | 210201011021222121111000200 |
4 | 1121032111301333312100 |
5 | 1300424132344240102 |
6 | 21012423550415200 |
7 | 1201660403435115 |
oct | 131162561776620 |
9 | 23634258544020 |
10 | 6131431243152 |
11 | 1a543640aa766 |
12 | 83038bb01500 |
13 | 356264901b67 |
14 | 172a973c090c |
15 | a975c7b351c |
hex | 59395c7fd90 |
6131431243152 has 60 divisors (see below), whose sum is σ = 17159684805120. Its totient is φ = 2043787402944.
The previous prime is 6131431243103. The next prime is 6131431243183. The reversal of 6131431243152 is 2513421341316.
6131431243152 is a `hidden beast` number, since 6 + 1 + 31 + 431 + 2 + 43 + 152 = 666.
It is a super-3 number, since 3×61314312431523 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 16771849 + ... + 17133527.
It is an arithmetic number, because the mean of its divisors is an integer number (285994746752).
Almost surely, 26131431243152 is an apocalyptic number.
It is an amenable number.
6131431243152 is an abundant number, since it is smaller than the sum of its proper divisors (11028253561968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6131431243152 is a wasteful number, since it uses less digits than its factorization.
6131431243152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 479420 (or 479411 counting only the distinct ones).
The product of its digits is 51840, while the sum is 36.
Adding to 6131431243152 its reverse (2513421341316), we get a palindrome (8644852584468).
The spelling of 6131431243152 in words is "six trillion, one hundred thirty-one billion, four hundred thirty-one million, two hundred forty-three thousand, one hundred fifty-two".
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