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6412420455503 is a prime number
BaseRepresentation
bin101110101010000001000…
…0010110001110001001111
3211201000120121101102202112
41131110002002301301033
51320030114114034003
621345454132414235
71231165520354546
oct135240202616117
924630517342675
106412420455503
1120525461a2907
1287692a77737b
133768c4c86a9a
1418251177b15d
15b1c05ea63d8
hex5d5020b1c4f

6412420455503 has 2 divisors, whose sum is σ = 6412420455504. Its totient is φ = 6412420455502.

The previous prime is 6412420455479. The next prime is 6412420455527. The reversal of 6412420455503 is 3055540242146.

It is a balanced prime because it is at equal distance from previous prime (6412420455479) and next prime (6412420455527).

It is a cyclic number.

It is not a de Polignac number, because 6412420455503 - 230 = 6411346713679 is a prime.

It is a super-2 number, since 2×64124204555032 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6412420155503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3206210227751 + 3206210227752.

It is an arithmetic number, because the mean of its divisors is an integer number (3206210227752).

Almost surely, 26412420455503 is an apocalyptic number.

6412420455503 is a deficient number, since it is larger than the sum of its proper divisors (1).

6412420455503 is an equidigital number, since it uses as much as digits as its factorization.

6412420455503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 6412420455503 its reverse (3055540242146), we get a palindrome (9467960697649).

The spelling of 6412420455503 in words is "six trillion, four hundred twelve billion, four hundred twenty million, four hundred fifty-five thousand, five hundred three".