Base | Representation |
---|---|
bin | 101110101010001001100… |
… | …0100001011000000100100 |
3 | 211201001022111202022101210 |
4 | 1131110103010023000210 |
5 | 1320031210221034300 |
6 | 21345542333351420 |
7 | 1231205555630211 |
oct | 135242304130044 |
9 | 24631274668353 |
10 | 6412706033700 |
11 | 2052682416a4a |
12 | 8769aa338570 |
13 | 37693c1a5475 |
14 | 18253b678b08 |
15 | b1c210b7050 |
hex | 5d51310b024 |
6412706033700 has 36 divisors (see below), whose sum is σ = 18554096125040. Its totient is φ = 1710054942240.
The previous prime is 6412706033623. The next prime is 6412706033707. The reversal of 6412706033700 is 73306072146.
It is a super-2 number, since 2×64127060337002 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (6412706033707) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10687843090 + ... + 10687843689.
Almost surely, 26412706033700 is an apocalyptic number.
6412706033700 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
6412706033700 is an abundant number, since it is smaller than the sum of its proper divisors (12141390091340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6412706033700 is a wasteful number, since it uses less digits than its factorization.
6412706033700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21375686796 (or 21375686789 counting only the distinct ones).
The product of its (nonzero) digits is 127008, while the sum is 39.
The spelling of 6412706033700 in words is "six trillion, four hundred twelve billion, seven hundred six million, thirty-three thousand, seven hundred".
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