Base | Representation |
---|---|
bin | 11101010000000111010001… |
… | …01001001111111101100101 |
3 | 22102202102221002011212211122 |
4 | 32220003220221033331211 |
5 | 31412401240314233133 |
6 | 344450352235143325 |
7 | 16356231504005156 |
oct | 1650035051177545 |
9 | 272672832155748 |
10 | 64325333352293 |
11 | 195502477a0562 |
12 | 726a81bba4b45 |
13 | 29b7b11ab68c0 |
14 | 11c551153792d |
15 | 7683b22da498 |
hex | 3a80e8a4ff65 |
64325333352293 has 64 divisors (see below), whose sum is σ = 75390103891200. Its totient is φ = 54378359285760.
The previous prime is 64325333352283. The next prime is 64325333352347. The reversal of 64325333352293 is 39225333352346.
It is a cyclic number.
It is not a de Polignac number, because 64325333352293 - 24 = 64325333352277 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (64325333352223) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5099917055 + ... + 5099929667.
It is an arithmetic number, because the mean of its divisors is an integer number (1177970373300).
Almost surely, 264325333352293 is an apocalyptic number.
It is an amenable number.
64325333352293 is a deficient number, since it is larger than the sum of its proper divisors (11064770538907).
64325333352293 is a wasteful number, since it uses less digits than its factorization.
64325333352293 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18502.
The product of its digits is 31492800, while the sum is 53.
Adding to 64325333352293 its sum of digits (53), we get a palindrome (64325333352346).
The spelling of 64325333352293 in words is "sixty-four trillion, three hundred twenty-five billion, three hundred thirty-three million, three hundred fifty-two thousand, two hundred ninety-three".
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