Base | Representation |
---|---|
bin | 101110111101111100010… |
… | …1100010101111101100111 |
3 | 211212010000220120202110011 |
4 | 1131323320230111331213 |
5 | 1321230234043034310 |
6 | 21421252314511051 |
7 | 1234242126213532 |
oct | 135737054257547 |
9 | 24763026522404 |
10 | 6455213252455 |
11 | 2069705659600 |
12 | 883091a35487 |
13 | 37a954813b06 |
14 | 184610c15a19 |
15 | b2dacc5378a |
hex | 5def8b15f67 |
6455213252455 has 48 divisors (see below), whose sum is σ = 9016261541280. Its totient is φ = 4418085816320.
The previous prime is 6455213252417. The next prime is 6455213252459. The reversal of 6455213252455 is 5542523125546.
It is a de Polignac number, because none of the positive numbers 2k-6455213252455 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6455213252399 and 6455213252408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6455213252459) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 122025651 + ... + 122078539.
It is an arithmetic number, because the mean of its divisors is an integer number (187838782110).
Almost surely, 26455213252455 is an apocalyptic number.
6455213252455 is a deficient number, since it is larger than the sum of its proper divisors (2561048288825).
6455213252455 is a wasteful number, since it uses less digits than its factorization.
6455213252455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64800 (or 64789 counting only the distinct ones).
The product of its digits is 7200000, while the sum is 49.
The spelling of 6455213252455 in words is "six trillion, four hundred fifty-five billion, two hundred thirteen million, two hundred fifty-two thousand, four hundred fifty-five".
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