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650000000000003 is a prime number
BaseRepresentation
bin1001001111001010111110101…
…1000110101010000000000011
310011020110101121121001102212012
42103302233223012222000003
51140144100000000000003
610222233513325523135
7253624643642001302
oct22362575306520003
93136411547042765
10650000000000003
111791234a7598034
1260a9a430a134ab
1321b8c97722c8b3
14b67224c876439
155022ed1d2c8d8
hex24f2beb1aa003

650000000000003 has 2 divisors, whose sum is σ = 650000000000004. Its totient is φ = 650000000000002.

The previous prime is 649999999999957. The next prime is 650000000000017. The reversal of 650000000000003 is 300000000000056.

It is a happy number.

It is an a-pointer prime, because the next prime (650000000000017) can be obtained adding 650000000000003 to its sum of digits (14).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-650000000000003 is a prime.

It is not a weakly prime, because it can be changed into another prime (650000080000003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325000000000001 + 325000000000002.

It is an arithmetic number, because the mean of its divisors is an integer number (325000000000002).

Almost surely, 2650000000000003 is an apocalyptic number.

650000000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

650000000000003 is an equidigital number, since it uses as much as digits as its factorization.

650000000000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 14.

Adding to 650000000000003 its reverse (300000000000056), we get a palindrome (950000000000059).

The spelling of 650000000000003 in words is "six hundred fifty trillion, three", and thus it is an aban number.