Base | Representation |
---|---|
bin | 111100100011000110… |
… | …001110011001100101 |
3 | 20012210220002001121220 |
4 | 330203012032121211 |
5 | 2031121404000340 |
6 | 45511113330553 |
7 | 4461043206342 |
oct | 744306163145 |
9 | 205726061556 |
10 | 65013343845 |
11 | 2563237953a |
12 | 10724a06a59 |
13 | 61912ab638 |
14 | 320a6297c9 |
15 | 1a57942ed0 |
hex | f2318e665 |
65013343845 has 64 divisors (see below), whose sum is σ = 108848323584. Its totient is φ = 33108341760.
The previous prime is 65013343799. The next prime is 65013343859. The reversal of 65013343845 is 54834331056.
65013343845 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 65013343845 - 29 = 65013343333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65013343797 and 65013343806.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6758259 + ... + 6767871.
It is an arithmetic number, because the mean of its divisors is an integer number (1700755056).
Almost surely, 265013343845 is an apocalyptic number.
It is an amenable number.
65013343845 is a deficient number, since it is larger than the sum of its proper divisors (43834979739).
65013343845 is a wasteful number, since it uses less digits than its factorization.
65013343845 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9902.
The product of its (nonzero) digits is 518400, while the sum is 42.
The spelling of 65013343845 in words is "sixty-five billion, thirteen million, three hundred forty-three thousand, eight hundred forty-five".
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